vlc%2F1%2E1%2E5
This is hexadecimal escaped character. '%' and two hex string indicates encoded character. if you replace this string with
It will showperl -e 'my $s="vlc%2F1%2E1%2E5"; $s=~ s/%(..)/chr(hex($1))/eg; print +$s;';
here, %2F='/', %2E='.'vlc/1.1.5
So, How about replacing $word[6] with this regex or using module like URI::Escape?
In reply to Re: a perl, awstats and SHOUTCast history
by remiah
in thread a perl, awstats and SHOUTCast history
by alexolivan
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