I got the following output: 
C:\Old_Data\perlp>perl t33.pl
david
        Website: www.facebook.com, Category: Social Networking
john
        Website: www.yahoo.com, Category: Entertainment
        Website: www.yahoo.com, Category: Entertainment
        Website: www.yahoo.com, Category: Entertainment
        Website: www.facebook.com, Category: Social Networking
mike
        Website: www.google.com, Category: Search Engines


Name: john
        Website Count
        www.yahoo.com       3
        www.facebook.com    1

        Type Count
        Entertainment       3
        Social Networking   1


Name: mike
        Website Count
        www.google.com      1

        Type Count
        Search Engines      1


Name: david
        Website Count
        www.facebook.com    1

        Type Count
        Social Networking   1

[download]
From this data: 
user="john" website="www.yahoo.com" type="Entertainment"
user="john" website="www.yahoo.com" type="Entertainment"
user="john" website="www.yahoo.com" type="Entertainment"
user="david" website="www.facebook.com" type="Social Networking"
user="john" website="www.facebook.com" type="Social Networking"
user="mike" website="www.google.com" type="Search Engines"

[download]
Notice that there are quotes surrounding every field. The regular expression that captures these fields from the file would need to be changed if thats not the case.

In my program I use 2 hashes - one to count the number of sites visited by each user, %count, and one to count each address and category (by user), %data. It seems to work OK for this small data set. 

#!/usr/bin/perl
use strict;
use warnings;

my (%data, %count);

while (<DATA>) {
    my ($user, $site, $cat) = /"([^"]+)"/g;
    $data{$user}{ qq{$site$;$cat} }++;
    $count{$user}++;
}

for my $user (sort keys %data) {
    my $href = $data{$user};
    print $user, "\n";
    for my $key (keys %$href) {
        my $str = sprintf "\tWebsite: %s, Category: %s\n", split /$;/,
+ $key;
        print $str x $href->{$key};
    }
}

my @ordered = sort {$count{$b} <=> $count{$a}} keys %count;

print "\n\n";

for my $user (@ordered) {
    my $href = $data{$user};
    print "Name: $user\n\tWebsite Count\n";
    for my $key (sort {$href->{$b} <=> $href->{$a}} keys %$href) {
        printf "\t%-20s%d\n", (split /$;/, $key)[0], $href->{$key};
    }
    print "\n";
    print "\tType Count\n";
    for my $key (sort {$href->{$b} <=> $href->{$a}} keys %$href) {
        printf "\t%-20s%d\n", (split /$;/, $key)[1], $href->{$key};
    }
    print "\n\n";
}

[download]
The line $data{$user}{ qq{$site$;$cat} }++; uses a 'compound' key ($site and $cat joined by $;).

Here is a dump of %data. 

$VAR1 = {
          'john' => {
                      'www.yahoo.com‡˜Entertainment' => 3,
                      'www.facebook.com‡˜Social Networking' => 1
                    },
          'mike' => {
                      'www.google.com‡˜Search Engines' => 1
                    },
          'david' => {
                       'www.facebook.com‡˜Social Networking' =>
                     }
        };

[download]

Update: Whoops, that doesn't count the categories correctly :-(
If there was another site with the same category, it wouldn't be totaled with the same category from another site.

In reply to Re^7: Hash of Hashes from file by Cristoforo
in thread Hash of Hashes from file by cipher

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