Re: Print some lines in a range

-p + <>???
-p + print???

Your code should be

perl -e"@lines=<>; print @lines[41900..50000];" data02.log > data03.lo
+g
[download]

As for your question,

perl -ne"next if $.<41901; print; exit if $.==50001;" data02.log > dat
+a03.log
[download]

($. is one-based while arrays are zero-based. That's why I changed the indexes by one.)

Comment on Re: Print some lines in a range Select or Download Code

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Re^2: Print some lines in a range by ranrodrig (Novice) on Mar 06, 2010 at 04:15 UTC
Folks thanks a lot for your answers you saved my Soul & the best solution is the one that ikegami post `time perl -ne"next if $.<41901; print; exit if $.==50001;" data02.log > data03.log` real 0m0.26s The next one also works but is slower to run `time perl -ne "print if 41901 .. 50001" data02.log > data03.log` real 0m33.21s An this one runs too but it takes a lot of time to run `time perl -e"@lines=<>; print @lines[41900..50000];" data02.log > data03.log` real 1m9.42s	[reply] [d/l] [select]
Re^3: Print some lines in a range by ikegami (Patriarch) on Mar 06, 2010 at 23:19 UTC
The first stops when enough has been read. Both the second and the third read the entire file. The difference is that the third loads the entire file into memory. And since we're talking about at least 50,000 lines, you might be running into swapping issues. The third definitely has a lot more memory allocations (one per line) than the second (almost none), and those aren't cheap.	[reply]