Re^2: Reading binary file in perl having records of different length

Thanks andal. All great suggestions. The binary length suggestion didn't seem to work in my case. I want to capture highest nibble first.

For example, the binary length in hex is 0x03 0x50 so I need to read next 848 bytes. However if I do unpack('s', $buffer) it returns 20483 bytes (reading the binary data as 0x50 0x03).

Comment on Re^2: Reading binary file in perl having records of different length

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Re^3: Reading binary file in perl having records of different length by Anonymous Monk on Jun 17, 2014 at 16:13 UTC
See pack patterns "n" and "v" instead, or the "<" and ">" modifiers if you really want signed interpretation. `$ perl -le 'print unpack("v","\x03\x50")' 20483 $ perl -le 'print unpack("n","\x03\x50")' 848 $ perl -le 'print unpack("s<","\x03\x50")' 20483 $ perl -le 'print unpack("s>","\x03\x50")' 848` [download]	[reply] [d/l]
Re^4: Reading binary file in perl having records of different length by jaypal (Beadle) on Jun 17, 2014 at 16:33 UTC
Awesome!! The use of "n" pattern worked great.	[reply]