Thanks, i think this will help me int($whatever)

because i did some little demonstration and works good

$string = "1.00";
if (int ($string > 1)) {
print "Yes true";
} else {
  print "Not true";
}
[download]

tho with 1:00, isn't working

am getting this error Argument "1:00" isn't numeric in numeric gt (>) at HelloWorld.pl line 4.

$string = "1:00";
if (int ($string > 3)) {
print "Yes true";
} else {
  print "Not true";
}
[download]

int( $string > 3 ) should be int( $string ) > 3.

You'll still get the warning unless you turn it off, though.

my $string = "1:00";
if ( do { no warnings qw( numeric ); int( $string ) } > 3 ) {
   say ">= 4";
} else {
   say "< 4";
}
[download]

It would be clearer to use >= 4 than > 3. And if you do that, you don't even need int.

my $string = "1:00";
if ( do { no warnings qw( numeric ); $string >= 4 } ) {
   say ">= 4";
} else {
   say "< 4";
}
[download]

> tho with 1:00, isn't working

Because ":" is not "."

Use  @digits = split /[:.]/, $string

And pick what you need

For anything more complicated, better consider a dedicated DateTime module.

Cheers Rolf
_{(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery}