in reply to Ignore a range of numbers ina List

> Not looking for any grep or regex solution for this task

> It is not that I didn't want to use Regex , But just wanted to try out the Non-Regex solution .

Please note that to be able to kill a chicken using only the tongue does not make you a better chef

But do you like banning elements using a blacklist hash?

perl -e "$h{6}=$h{7}=1;for (@ARGV){print qq($_ ) unless exists $h{$_}} +" 1 6 2 2 7 1 6 99 99 7 1 2 2 1 99 99

L*

There are no rules, there are no thumbs..
Reinvent the wheel, then learn The Wheel; may be one day you reinvent one of THE WHEELS.

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Re^2: Ignore a range of numbers in a List -- oneliner
by afoken (Chancellor) on Jun 27, 2017 at 05:01 UTC
    perl -e "$h{6}=$h{7}=1;for (@ARGV){print qq($_ ) unless exists $h{$_}}" 1 6 2 2 7 1 6 99 99 7

    In this case, exists is not needed, because all numbers in the blacklist have values that evaluate to true:

    >perl -e "$h{6}=$h{7}=1;for (@ARGV){print qq($_ ) unless $h{$_}}" 1 6 +2 2 7 1 6 99 99 7 1 2 2 1 99 99 >

    And for the same reason, we can shorten that a little bit more by using OR instead of postfix unless:

    >perl -e "$h{6}=$h{7}=1;for(@ARGV){$h{$_}||print qq($_ )}" 1 6 2 2 7 1 + 6 99 99 7 1 2 2 1 99 99 >

    Switching to postfix for gets rid of a few more characters:

    >perl -e "$h{6}=$h{7}=1;$h{$_}||print qq($_ )for@ARGV" 1 6 2 2 7 1 6 9 +9 99 7 1 2 2 1 99 99 >

    Alexander

    --
    Today I will gladly share my knowledge and experience, for there are no sweeter words than "I told you so". ;-)