my $paco = $foo->bar;
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Is this a scalar or a call to a class method with no paramaters? Let's sift through the code to find out, oh joy!

Let's sift indeed:

my $paco =
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Ah, we're creating a lexically scoped scalar called $paco

$foo
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It has something to do with another scalar, called $foo

->
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The arrow indicates we're either going to dereference, or have method call.

bar
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No [] or {}, so it's a method call. Neato, we're using objects!
But we can't see whether $foo is a scalar holding a blessed reference (better known as object) or a scalar holding a package name. That's only because it's called $foo, because a good name would tell us.

And do you really put package names in scalars and then use those to call class methods? It's ugly, just like using soft references.

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