RE: Re: Numbers....

What if your number is 191928219.19292?

$a = 1034341.8766756;
my ($l, $r) = split /\./, $a;
$a = substr($a, 0, (length $l) + 2);
[download]

There is probably a bunch of ways to do this. Benchmarking them would be good.

Cheers,
KM

Comment on RE: Re: Numbers.... Download Code

Replies are listed 'Best First'.
RE: RE: Re: Numbers.... by kirbyk (Friar) on Jun 03, 2000 at 02:17 UTC
You could also be clever and do this with a regex. (I've actually done this!) ($trunc_num) = ($fullnum =~ /(.*\.\d\d)/); This will take all the values up to the decimal, the literal period, and the next two digits, and stick them in $trunc_num. You might want to be sure you have the right number of digits, so that something that's a buck fifty comes out as 1.50 rather than 1.5 - there are also lots of ways to do this. I tend to, being lazy, do something like: $fullnum .= "00" if $fullnum =~ /\./; $fullnum .= ".00" unless $fullnum =~ /\./; And then do the regex trick. The check for the literal period takes care of integer values, like '5', so they don't become 500. Okay, it's not pretty, but it is sort of a nifty way to do it. -- Kirby Tuxtops: Laptops with Linux!	[reply]

Replies are listed 'Best First'.

RE: RE: Re: Numbers....
by kirbyk (Friar) on Jun 03, 2000 at 02:17 UTC

($trunc_num) = ($fullnum =~ /(.*\.\d\d)/);

This will take all the values up to the decimal, the literal period, and the next two digits, and stick them in $trunc_num.

You might want to be sure you have the right number of digits, so that something that's a buck fifty comes out as 1.50 rather than 1.5 - there are also lots of ways to do this. I tend to, being lazy, do something like:

$fullnum .= "00" if $fullnum =~ /\./;

$fullnum .= ".00" unless $fullnum =~ /\./;

And then do the regex trick. The check for the literal period takes care of integer values, like '5', so they don't become 500.

Okay, it's not pretty, but it is sort of a nifty way to do it.

-- Kirby

Tuxtops: Laptops with Linux!

[reply]