Re: whitespace eliminator for arrays

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Re**2: whitespace eliminator for arrays by belg4mit (Prior) on Oct 22, 2002 at 18:59 UTC
That also ignores Unicode. A slightly more complete substitution would be `=~ s/[[:space:]]//g` [download] `-- perl -wpe "s/\b;([mnst])/'$1/g"`	[reply] [d/l]
Re^3: whitespace eliminator for arrays by Aristotle (Chancellor) on Oct 22, 2002 at 19:26 UTC
Or, of course, `s/[[:space:]]+//g;` `;-)` Makeshifts last the longest.	[reply] [d/l]
Re: Re: whitespace eliminator for arrays by markcsmith (Novice) on Oct 22, 2002 at 19:24 UTC
Out of curiosity, why would specifiying the hex for each type of whitespace and using tr be better than a s///? Also, how does putting the for after the statement increase efficiency? Not that I'm nagging, I'm curious.	[reply]
Re^3: whitespace eliminator for arrays by Aristotle (Chancellor) on Oct 22, 2002 at 19:36 UTC
You missed the little `+` I added to the regex. `:-)` Using `for` as expression modificator wasn't the point. The `+` will cause the regex to delete sequences of whitespace in one fell swoop, rather than character by character. `tr` is better in that it doesn't fire up the entire regex engine to do its job. It's therefor more efficient for the specific job of deleting all of a list of characters from a string. However, it doesn't understand classes like `\s` as the regex engine does, so you have to spell out all the characters. Doing so with hex codes is merely one choice out of several. Makeshifts last the longest.	[reply]
Re: Re^3: whitespace eliminator for arrays by markcsmith (Novice) on Oct 22, 2002 at 22:25 UTC
I see. Thanks for the reply.	[reply]