in reply to Re: Zero Padding to the Right of the Decimal
in thread Zero Padding to the Right of the Decimal

I agree whole-heartedly, the number probably shouldn't be baked into a format until you plan to display it. <insert standard disclaimer about being appropriate for the rest of your script and your coding style>

So it might look like this with only one print/printf/sprintf: 

my $i=0;
while ($i <=100){
    $i=$i+0.01;
    printf("%3.2f\n",$i);
}

[download]

-Kurt

Replies are listed 'Best First'.
Re: Re: Re: Zero Padding to the Right of the Decimal
by Cody Pendant (Prior) on Jan 15, 2004 at 20:40 UTC

    Just one more thing, how about this:

        printf( "%3.2f\n" , ($i + 0.01)  );

    [download]

    Instead of the two lines above?


    ($_='kkvvttuubbooppuuiiffssqqffssmmiibbddllffss')
    =~y~b-v~a-z~s; print
[reply]
[d/l]
      you'll never exit the loop that way, because you never modify $i.
      You could use +=, though : 
      my $i=0;
while ($i <=100){    
    printf("%3.2f\n",$i+=0.01);
}

      [download]
[reply]
[d/l]

        This thread is probably already too deep for anyone to care, but if I were doing this, I would do so thusly:

            printf "%3.2f\n", $_/100 for 0 .. 100*100;
[reply]
[d/l]
          printf( "%3.2f\n" , ($i + 0.01)  );

      doesn't work.

      Change to:

          printf( "%3.2f\n" , ($i += 0.01)  );

      dave

[reply]
[d/l]
[select]

In Section Seekers of Perl Wisdom