Hello,

In the following code, note the order of the printf statements; in particular, note the order of the second and the third printfs: 

#!/c/opt/perl64/bin/perl
BEGIN {(*STDERR = *STDOUT) || die;}
use diagnostics;
use warnings;
use strict;
$| = 1;

my   @foo;
push @foo, 5;
push @foo, 7, 8;

printf  "@foo\n";
printf  "\nabove first set of dashes #:  [" . #@foo . "]\n";
printf  "first set of dashes------------\n";
printf  "\nsecond set of dashes------------\n";

my $y = printf  "\ny dashes------------\n";
printf "\ny: [$y]\n";

__END__

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The output of the above code using perl 5, version 16, subversion 1 (v5.16.1) built for MSWin32-x64-multi-thread (with 1 registered patch) is given below -- note the reversal of the outputs from the second and third printf statements: 

5 7 8
first set of dashes------------

above first set of dashes #:  [1
second set of dashes------------

y dashes------------

y: [1]

$

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Question: why is the order of the output lines different from the order of the printf statements?

Thanks,

In reply to Order of printf statements vs order of actual lines printed out by sg

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