I want to remove the trailing slash in the path but the code print nothing. Why?
Added exactly one line to your code and got results. Here's the new code:
#!/usr/bin/perl -w
use strict;
use warnings;
sub main
{
my $path = "\\\\127.0.0.1\\c$\\bak\\";
$path =~ s/\\$//;
print __FILE__.__LINE__." path $path\n";
return;
}
main();
and here are the results:
$ ./hackslash.pl
Use of uninitialized value $\ in concatenation (.) or string at ./hack
+slash.pl line 6.
./hackslash.pl8 path \\127.0.0.1\ak
What I think you really wanted was to add a backslash before the $ since normally that would have been interpoloated resulting in :
# note the backslash in front of the dollar sign
my $path = "\\\\127.0.0.1\\c\$\\bak\\";
giving you:
$ ./hackslash.pl
./hackslash.pl8 path \\127.0.0.1\c$\bak
Creating a sub without calling it will act as a NOOP.
Peter L. Berghold -- Unix Professional
Peter -at- Berghold -dot- Net; AOL IM redcowdawg Yahoo IM: blue_cowdawg
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