A few points, if I may:

All in all, this problem seems like a nice little assignment for a competent cryptanalyst.

Modulo cmps. Since (2**31)%1000003 == 477207, we know we may safely add small values to the hashval without fear of sign change or overflow. This allows one to rewrite tests such as
    v %= 1001; if (v < 0) v += 1001; if (v != 100) continue;
in a simpler, speedier form:
    v += 1001 - 100; if (v % 1001) continue;

(*) Updated.


In reply to Re: The 10**21 Problem (Part 3) by oiskuu
in thread The 10**21 Problem (Part 3) by eyepopslikeamosquito

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