Set::CrossProduct provides a solution.
#!/usr/bin/perl use strict; use warnings; use Set::CrossProduct; my %hash=('ID' => { 'key1' => ['key1_val1', 'key1_val2'], 'key2' => ['key2_val1', 'key2_val2'] } ); for my $id (keys %hash) { my @data = values %{ $hash{$id} }; my $cp = Set::CrossProduct->new( \@data ); my $i = 1; while( my $array_ref = $cp->get ) { print join( " ", $id, $i++, @$array_ref ), "\n"; } }
This prints
ID 1 key2_val1 key1_val1 ID 2 key2_val1 key1_val2 ID 3 key2_val2 key1_val1 ID 4 key2_val2 key1_val2
Note that my @data = values %{ $hash{$id} }; does not give values corresponding to 'key1', 'key2' ... 'key15' order. Some change in how the order of values appear would need to be made to get that.

Hope this helps,

Chris

Update: You will get huge amount of combinations for 12 rows with 15 items in each array. 15 ^ 12 = 129,746,337,890,625


In reply to Re: Massive expansion of a hash of arrays? by Cristoforo
in thread Massive expansion of a hash of arrays? by Amblikai

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