I have the following script that prints files names for the given folder. 
my $directory = ".\\folder";
opendir (DIR, $directory) or die $!;
                         while (my $fldr = readdir(DIR)) {
                         if ($fldr =~ m/log?/){
                         print $fldr, "\n";
                         } }

[download]
OUTPUT 
(10.10.10.1).log
(10.10.10.2).log
..................
..................
Press any key to continue . . .

[download]
I am only interested in the first file. How can I print the first match only that ends with .log? Tried with $fldr[0], didn't work. Tried, m/log?/... thinking that ? symbol will trigger not to be greedy, but still didn't work.

Please let me know.

UPDATED: Script & output.

In reply to regex 1st match only by ArifS

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