One way: 

c:\@Work\Perl\monks>perl -wMstrict -le
"my %fill = (
   '\bM(ary)\b'  => 'G$1',
   '\bL(arry)\b' => 'B$1',
   );
 ;;
 my $s = 'Mary has a little lamb, Larry has a big one';
 print qq{'$s'};
 ;;
 foreach my $key (keys %fill) {
   $s =~ s/$key/ qq{qq{$fill{$key}}} /gee;
   }
 print qq{'$s'};
"
'Mary has a little lamb, Larry has a big one'
'Gary has a little lamb, Barry has a big one'

[download]
See also the discussions linked from the Re: Evaluating $1 construct in literal replacement expression node and also its root.

Give a man a fish:  <%-(-(-(-<

In reply to Re: backreference on hash by AnomalousMonk
in thread backreference on hash by marcpascual

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