Hello All,
How do I test for a directory structures existence and if it does not exist, create it?
e.g.
Test for the structure dir1/dir2/dir3
if it exists, create the file 'filename.txt' in the directry dir1/dir2/dir3.
The initial code I used was: 
$fileName = "dir1/dir2/dir3/filename.txt"; 
open (LIST, ">$fileName");.....

[download]
This works if the directory already exists, but does not work without the directories.
I've looked at the manuals but have not been able to find the answer?
Any help would be appreciated.

Thank you

In reply to file creation by amulcahy

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