can someone tell me why this doesn't loop through over and over until i enter number 7 to exit. I'm pretty much a rookie but trying, also if there is a better or cleaner way that is not to confusing I would be interested in your opinions. Thanks Bob 
#!/usr/bin/perl -w

START: {
&menu;
$input= (<STDIN>);
chomp $input;
if ($input == 1) {
print "You have chosen option 1\n";
}
if($input == 2) {
print "You have chosen option 2\n";
}
if ($input == 3) {
print "You have chosen option 3\n";
}
if($input == 4) {
print "You have chosen option 4\n";
}
if ($input == 5) {
print "You have chosen option 5\n";
}
if($input == 6) {
print "You have chosen option 6\n";
  } else {
exit;
  }
#redo START unless $input >= 7;
redo START;
}

sub menu {
print "Enter a number for the option you want\n";
print "1) Cancel FINAL Schedule for machine A:   \n";
print "2) Submit new FINAL schedule:    \n";
print "3) Ignore Wrkld:    \n";
print "4) Run around the block:   \n";
print "5) Buy a new car:    \n";
print "6) order Pizza:   \n\n";
print "7) exit:   \n\n";
}

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In reply to simple menu loop problems by ddrumguy

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