Hi,

(Now I call *this* node archaeology)

this is for german, very dumb. But a nice recursive aproach, suitable for numbers up to 999 999 999 with nice german grammar. Easily extendable.

sub de_number {
    my $positive = shift;
    my $out;

    my @tokens1 = qw(null ein zwei drei vier fünf sechs sieben acht ne
+un zehn elf zwölf);
    my @tokens2 = qw(zwanzig dreissig vierzig fünfzig sechzig siebzig 
+achtzig neunzig hundert);
#    my @tokens3 = qw(million milliarde billion billiarde); # Not need
+ed now

    if($positive >= 0 && $positive <= 12) {
    $out = $tokens1[$positive];
    } elsif($positive >= 13 && $positive <= 19) {
    $out = $tokens1[$positive-10].'zehn';
    } elsif($positive >= 20 && $positive <= 100) {
    my $one_idx = int $positive/10-2;
    my $ten_idx = $positive-($one_idx+2)*10;
    
    $out = $tokens1[$ten_idx].'und' if $ten_idx;
    $out .= $tokens2[$one_idx];
    } elsif($positive >= 101 && $positive <= 999) {
    my $one_idx = int $positive/100;

    $out = $tokens1[$one_idx].'hundert'.&de_number($positive-$one_idx*
+100);
    } elsif($positive >= 1000 && $positive <= 999999) {
    my $one_idx = int $positive/1000;
    my $tausend = $positive-$one_idx*1000;
    my $nonull = $tausend ? &de_number($tausend) : '';

    $out = &de_number($one_idx).'tausend'.$nonull;
    } elsif($positive >= 1000000 && $positive <= 999999999) {
    my $one_idx = int $positive/1000000;
    my $mio     = $positive-$one_idx*1000000;
    my $nonull  = $mio ? ' '.&de_number($mio) : '';
    my $one     = $one_idx == 1 ? 'e' : '';

    $out = &de_number($one_idx).$one.' million';
    $out .= 'en' if $one_idx > 1;
    $out .= $nonull;
    }

    return $out;

}

[download]

Bye
 PetaMem

In reply to Re: number 2 text by PetaMem
in thread number 2 text by Prince99

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