okay, i'll bite. why does this work?

I mean, using an explicit END block i understand...

perl -lane '$s+=$F[2]; END{print $s/$.;}'

But what is it about your "}{" that makes the print part of an implicit END block? Is this documented behavior? or an unintenional artifact of the way the parser deals with -n ?

In reply to Re: Re: Re: Basic arithmetic functions by hossman
in thread Basic arithmetic functions by KristiePi

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