Don't confuse creating a closure with compilation. The closure's body is compiled at compile time, not when the closure gets created. The code of this closure says "stringify $j", but which $j is only decided at runtime. Creating a closure at runtime does not compile the code; it merely "connects" it with a specific instance of whichever lexicals it refers to. Since you only create a single $j, all your closures get "connected" to the same $j.

Makeshifts last the longest.

In reply to Re^2: Closure Confusion by Aristotle
in thread Closure Confusion by Dinosaur

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