print "@$_[1]\n";   # Does Not work, why ?

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Because it's parsed as @{$_}[1] - a slice (one element long, usually broken) of the array pointed to by the $_ variable.

The syntax is very predictable, once you learn the rules in perlref (and perlreftut).

-- Randal L. Schwartz, Perl hacker
Be sure to read my standard disclaimer if this is a reply.

In reply to •Re: Pass by ref an array weirdness by merlyn
in thread Pass by ref an array weirdness by aennen

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