Thanks. I did test it myself as well. ;-)

See below.

#!/usr/bin/perl -wl use strict; use Date::Calc 'Day_of_Week'; sub day_of_week { my ($year, $month, $day) = @_; my @offset = (0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4); $year -= $month < 3; return ($year + int($year/4) - int($year/100) + int($year/400) + $offset[$month-1] + $day) % 7; } my @days = (31,27,31,30,31,30,31,31,30,31,30,31); for (1..1000) { my $year = 1753 + int rand 4000; my $month = 1 + int rand 12; my $day = 1 + int rand $days[$month-1]; my @date = ($year,$month, $day); my $wd1 = day_of_week(@date); my $wd2 = Day_of_Week(@date); $wd2 = 0 if $wd2 == 7; print "@date:\t$wd1 != $wd2" if $wd1 != $wd2 ; }

--
John.


In reply to Re: Re: Day of the week by jmcnamara
in thread Day of the week by jmcnamara

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