#!/usr/bin/perl -w use strict; my $string = "abacab"; print "$string\n"; my $pattern = "a"; my $better = "A"; my $n=1; my $i=0; $string =~ s/($pattern)/$i == $n ? $better : $1; i++/ge; print "$string\n"
Nuance
In reply to RE: RE: Selective substitution: not in Perl?
by nuance
in thread Selective substitution: not in Perl?
by Anonymous Monk
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