I disagree with the last piece of advice. Perl does have a defined order of evaluation; it is just not the same as your (or my) assumptions. Imagine that Perl did not have such a defined order of evaluation. How can I trust 
print 5+1;

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always prints 6, and not 5 (and a warning)?

update: I see that I was confusing precedence and evaluation order.

In reply to Re: Re: Order of operations, mutators, aliasing and whammies by asarih
in thread Order of operations, mutators, aliasing and whammies by demerphq

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