One should perhaps add, that the real reason why this magic works is because "=~" binds more thightly than "=", so the regex gets done first and then its results are evaluated in list-context (which is provided by using an array as an L-value).

CountZero

"If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law

In reply to Re: Perl Idioms Explained - @ary = $str =~ m/(stuff)/g by CountZero
in thread Perl Idioms Explained - @ary = $str =~ m/(stuff)/g by tachyon

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