The next solution has the same assumption.
A quick look at the source of List::Compare leads me to think it does not make that assumption.
--
You said you wanted to be around when I made a mistake; well, this could be it, sweetheart.
In reply to Re^2: intersection of N arrays
by Solo
in thread intersection of N arrays
by basscakes
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |