Ok so japhy told you why that is slow, here's a way to make your code fast regardless - don't even bother with the capturing.

Capturing is always slow because it has to make a copy of the source string. $1, internally, is just substr( $safe_copy_of_match, $-[1], $+[1] - $-[1] ). So the largest speed hit (that I'm aware of) is the memory operation of making a safe duplicate of the data that was just matched. COW (copy on write) may mitigate this if/when it ever gets into perl.

Likely to be be fastest. This was my second thought.

my $whatever_index = index lc $text , $whatever;
return( substr( $text, 0, $whatever_index ),
        substr( $text, $whatever_index + length $whatever ) );

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This may be the fastest. It was my third thought.

my $whatever_index = index lc $text, $whatever' ;
my $whatever_length = length $whatever;
return unpack "a" . $whatever_index . "x" . $whatever_length . "a*", $
+text;

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This was my first thought. Use a plain regex to *locate* the thing in the string and then just substr() the equivalent of the captures out. This happens to be simplest to look at so it wins on the visual-complexity scale. This is a great general technique to avoid capturing on regexes and as such is a great post-bechmarking optimization.

if ( $text =~ /whatever/i )
{
    return( substr( $text, 0, $-[0] ),
        substr( $text, $+[0] );
}

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In reply to Re: The Deceiver by diotalevi
in thread Why does a Perl 5.6 regex run a lot slower on Perl 5.8? by perldeveloper

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