$/ = "\n>";
That is also clumsy, for several reasons:
  1. You have to delete the trailing ">", at the end of every string (but the last)
  2. You have to delete the leading ">", at the start of every line
  3. You still have to delete every newline, and chomp won't work, because of the changed setting for $/.

Oh well. Such is life.

s/^>//; s/>$//; tr/<n//d;

In reply to Re: How to avoid using array in concatenating string of multiple lines by Anonymous Monk
in thread How to avoid using array in concatenating string of multiple lines OR How To Read FASTA by monkfan

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