Hello everyone, I have a script (> 400 Lines) in wich I have implemented a timeout routine using SIG{ALRM}. The code used is the following: 
    $cmd="myCommand";
    # Timeout evaluation:
    eval {
      # Set action to be done when alarm occurs:
      local $SIG{ALRM} = sub { die "ALARM_COMMAND_TIMEOUT" };
      # Schedule alarm in $CMD_TIMEOUT seconds:
      alarm($CMD_TIMEOUT);

      ### execute the command that can block
      $childPID = open(PIPE, "-|");

      ### Unable to create child process
      unless(defined $childPID) {
         close(PIPE);
         die "ERROR_FORK_PROCESS: $!\n";
      }

      ### Child Process Created ... execute command
      unless($childPID) {
         exec($cmd) or die "ERROR_OPEN_PIPE : $!\n";

      ### Unable to create child process
      }
      wait;
      alarm(0);

      close(PIPE);
    };
    alarm(0);

[download]
During the test period, I noticed something strange. When using this code, my whole script is 'respawned' instead of the single command I want to check for timeout. Maybe the code is wrong. All I need is to run a single command and wait for the result withing a given timeout. If the command takes too long I want to kill it. The script is running on AIX 4.3.3 & 5.2. Perl version is 5.8. Any suggestions ? Thank you very much.

In reply to Timeout with SIG{ALRM} not working as expected by MorgothSauron

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