I'm following no modules approach to find the day of year based on the user provided date.
#!/usr/local/bin/perl
sub dayofyear {
($day1,$month,$year)=@_;
my(@d_in_m)=(0,31,28,31,30,31,30,31,31,30,31,30,31);
$d_in_m[2]=29 if (&leap($year));
for($i=1;$i<$month;$i++) {
$k += $d_in_m[$i];
}
$k += $day1;
return $k;
}
sub leap {
$y = shift;
return 0 unless $y % 4 == 0;
return 1 unless $y % 100 == 0;
return 0 unless $y % 400 == 0;
return 1;
}
print dayofyear(10,3,2005);
It's printing the correct value. Is there any way to optimize the above code / do it in a better way?
--Binoj
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