My solution in the root thread required was only minimally better than my original solution (to the wrong problem). This minimally tested version is vast improvement over both previous solutions.
#!/usr/bin/perl use strict; use warnings; my $end = shift || 22; my $next = lazy_merge( [ @ARGV ? @ARGV : (2, 3, 5) ] ); print $next->(), "\n" for 1 .. $end; sub lazy_merge { my ($list, $last) = (shift(), 0); my $by_n = sub { my ($n, $k) = (shift(), 0); return sub { $_[0] ? +$k += $n : $k } }; $_ = $by_n->( $_ ) for @$list; return sub { my $low; for ( @$list ) { my $val = $_->(); $val = $_->( 'next' ) if $val <= $last; $low = $val if ! defined $low || $val < $low; } return $last = $low; }; }

Cheers - L~R


In reply to Re: Challenge: Another Infinite Lazy List by Limbic~Region
in thread Challenge: Another Infinite Lazy List by Limbic~Region

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