That's kind of a boring brute force algorithm. Far more interesting would be to implement the algorithm referred to on the page you link to. Or to find all 100025 fang pairs of 1067781345046160692992979584215948335363056972783128881420721375504640.

In reply to Re: Vampire Numbers Revisited by Anonymous Monk
in thread Vampire Numbers Revisited by Limbic~Region

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