That's not my point. My point is that there are already operators where EXPR1 OP EXPR2 may cause one of the expression to not be evaluation, and people don't find that strange. Or inconvenient.

And in languages with lazy evaluation, this is common.

In reply to Re^36: Why is the execution order of subexpressions undefined? (magic ruts) by Anonymous Monk
in thread Why is the execution order of subexpressions undefined? by BrowserUk

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