What argument checking? 

sub f {
   my ($arg1,$arg2,$arg3) = @_;
   .... uses arg1, arg2 arg3 ....
}

f();        # Works. ($arg1, $arg2 and $arg3 are undef.)
f(1,2,3,4); # Works. ('4' is ignored.)

[download]

Maybe you're thinking of prototypes? & causes the prototype to be ignored. Use of & is discouraged for this reason. Then again, most prototypes are discouraged as well (for other reasons).

Aside from ignoring prototypes, (&f) means something different than f(): 

sub f {
   my ($arg1) = @_;
   print(defined($arg1) ? $arg1 : '[undef]', "\n");
}

sub t1 { print("t1: "); f(); }
sub t2 { print("t2: "); &f;  }

t1('moo');  # t1: [undef]
t2('moo');  # t2: moo

[download]

When function f is called using &f (with no arguments), a new @_ isn't created; it shares the @_ of its caller.

Looking at it from the other direction,
f(...);
is equivalent to
do { local @_ = (...); &f };
(when no prototypes are involved).

Update: Added talk of prototypes.

In reply to Re: calling f(arg1,arg2,arg3) better than &f by ikegami
in thread calling f(arg1,arg2,arg3) better than &f by edwardt_tril

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