It's nothing you can really help and can be ignored by you. It has to do with a function being declared with an empty prototype (e.g. sub foo () {...}) and another with no prototype (e.g. sub bar {...}) and then having the prototyped one become an alias to the unprototyped one: 
sub foo () { return "foo\n" }
sub bar    { return "bar\n" }
*foo = \&bar;

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Jeff japhy Pinyan, P.L., P.M., P.O.D, X.S.: Perl, regex, and perl hacker
How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart

In reply to Re: Prototype mismatch: sub B::OP::size: none vs () at by japhy
in thread Prototype mismatch: sub B::OP::size: none vs () at by Booger

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