This makes the most sense to me, but, I think this line: 
           $view[$v]=&{$dispatch[$d][0]} ($view[$v]);

[download]
should probably be this 
           $view[$v]=&{$dispatch[$d][1]} ($view[$v]);

[download]

In reply to Re^2: Using a regex function from a hash by Anonymous Monk
in thread Using a regex function from a hash by perlNinny

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