Excellent suggestions, monks.
I don't really see the problem in the same way, however. If the problem is here:
my $output; # this value is unintialized
open my $old_stdout, '>&=', \*STDOUT;
close STDOUT;
# Use of uninitialized value in open at the following line
open STDOUT, '>', \$output;
It's not an issue of 'spitting warnings at the second opening of a memory file'. $output really is uninitialized, and STDOUT, when its called, is already initialized. So it actually spits a warning the first time.
What I'm trying to say is that the warning is thrown more or less as expected. It's been pointed out that setting $output='' will fix the problem. Also... turning off 'use warnings' would probably silence it, but I wouldn't know because I never turn off warnings.
I hope this helps.
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