Could someone explains why this detects if a variable is tainted? 

        return ! eval {
            join('',@_), kill 0;
            1;
        };
    }

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I assume the key is "vairable,kill 0". I checked the kill func, it returns 0 on success and > 0 on failure. So kill 0 will always return success; Does this mean the variable you pass into this function is always going to come out tainted? Thanks.

In reply to is_tainted function by perlknight

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