I have the following code below, but I am trying to match a pattern in between two pounds ##pattern##, but the second \s* is not working as expected. It seems like it doesnt like the * or something needs be escaped? It works when there are no whitespaces between the period and ##, example "incorrecto.##pp'" Does anyone have any suggestion? 
$langhash{'dígito verificador incorrecto.'} = 'digit incorrect.';

my $string = '(5/4/07 4:24:03 PM CDT) 1473721:   ##   dígito verificad
+or incorrecto.##pp';  

if ($string =~ s/##\s*([^#]+)\s*##/##$langhash{$1}##/)
{
print "$langhash{$1}\n";
print "$1\n";
print $string;
}

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In reply to substitution not working correctly by qnguyen

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