Thanks. Could you tell me what I'm doing wrong with this?


perldl> $a=sequence(10)

perldl> $b=pdl[3,7,2]  

perldl> p which($a==$b->dummy)
[3 17 22]

[download]
I was expecting 3,7,2--so it's printing the column number of b in the tens-place!--I just want the index from $a.

In reply to Re^2: matching pdl elements by Blue_eyed_son
in thread matching pdl elements by Anonymous Monk

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