Hi,

I want to run an entire shell script inside a perl script. Below is my code. 
#!/usr/bin/perl

use strict;
use warnings;

my $a = do { local $/; <DATA> };
system($a, "option_1");

__DATA__
#!/bin/sh

echo "hello"
echo $1
echo "hi"

[download]

Basically, I want to run the shell script and supply it with arguments. When I run this, it will say something "Can't exec ... No such file or directory...". That is because of the presence of "$1" in the bash script.

But when I run change the system($a, "option_1") to just system("$a option_1"), then it would complain that option_1 command was not found which means that the shell is trying to execute another command.

Also, if I change the system($a, "option_1") to just system("$a"), then it would run fine except that the line echo $1 in the bash script will not give any output. This indicates to me that it is actually possible to run an entire bash script inside perl.

Any ideas on how to resolve running an entire bash script inside perl while supplying some arguments in the bash script?

Of course, I could just save the bash script in a separate file and simply call system against it with arguments and it will be fine. I'm just thinking if there is a way to do what I want.

Thanks in adance.

In reply to Running Entire Bash Script Inside Perl by bichonfrise74

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