My objection to the above answer (to which the @-response above is directed) is that writing \&$a no more guarantees that $a is a coderef than just writing $a does.

Well you're right but from the perspective of the prototyped function it's clearly the goal to get a coderef at that point and nothing else.

It delegates the problem to the code-dereferencing in &$a.

so it's not anymore a problem of the implementation of prototypes but of the implementation of &-dereferencing.

And you will agree that it doesn't make sense in a loosely typed language like perl to guarantee that the scalar following & is a coderef!

Otherwise it would become in consequence necessarily a typed language!

Cheers Rolf

UPDATE: To make it clearer "prototyping" is an option to make perl-functions more "strongly typed", and the function assures this "typing" within it's possibilities, it can't look ahead and alter the behaviour of &. And & can't be strongly typed!

Hence you see problems only at run-time...

In reply to Re^3: coderefs and (&) prototypes by LanX
in thread coderefs and (&) prototypes by LanX

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