The basic jist is that by using @{$foo->{'bar'}}, you're derefrencing the value of 'bar' as a list.. and you can work with it as a list because the corresponding value of 'bar' is a refrence to a list; not a list in and of itself.
Hope this helps..
Rich
In reply to Re: hashes of hashes of arrays in subroutine
by rchiav
in thread hashes of hashes of arrays in subroutine
by diarmuid
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