Question: When I am trying to put $Latest in cat command in 2nd part of this script, obviously it does not work as it's no more a command, could anyone please tell how to implement $Latest variable data in cat command or is there other way to do. 
my $Latest = `ssh root\@10.10.22.12 'cat /usr/local/LATEST'`;
print $Latest;

$path = `ssh root\@10.10.22.12 'cat /usr/local/$Latest/test.txt'`;

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In reply to How to: using file content in cat command by kapoor

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