Forgive me for not being as clear as I thought I was.
What I have working now (as seen in the code in my last post) is a pattern that is removed (in this case it's replaced by an asterisk for testing purposes) in $temp_seq and I would like to have the preceding or following 6 characters removed as well.

For example:
$temp = 1234567890;
$pattern = 123;

$temp =~ s/$pattern/*/i;

print "temp = $temp";

[download]
The output I would like to see is: temp = 0

Like wise, if the pattern removed was at the end of the string, I would like to remove the preceding 6 characters of the $temp.
As for the inversion of the pattern, consider the example mentioned earlier, where the pattern removed was found at the end of the string but it was inverted: 
$temp = 4567890321;
$pattern = 123;

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Instead of creating a whole new variable to match the 321, is there a simpler way to reverse the $pattern variable explicitly in a regex?

please, let me know if I need to re-clarify anything and thanks again!!

In reply to Re^2: Regex - remove characters (pattern not terminated) by twaddlac
in thread Regex - remove characters (pattern not terminated) by twaddlac

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