A better way would be to decode the lines, i.e. convert the "\n" into newlines. 
while (<DATA>) {
    s/\\n/\n/g;
    print "Matched: $1\n"
        if /DIP\s+\S+\s+(\S+).*?\n/;
    
}

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In reply to Re^4: Regex: Ignore \n in \S by ikegami
in thread Regex: Ignore \n in \S by manav_gupta

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