Hello Monks
Can anybody explan me why the following code prints '1'?
my $a = 1;
my $b = 0;
my $c = $a and $b;
print $c;

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did i have to use different literals for boolean algebra? but even then writing 
my $a = (1==1);
my $b = (1==0);
my $c = $a and $b;
print $c;

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the result is 1. but (1==0) evaluates to an empty string

please give me some clue
Thanks

In reply to strange boolean algebra behaviour by vlad_tepesch

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