Ok, I'm stumped. Why in the world does the second line below result in so much less memory usage than the first? Just because it allocates the space before starting to fill it? 

@a=1..9e6; 
$#a=9e6; $a[$_-1]=$_ for 1..9e6;

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Aaron B.
Available for small or large Perl jobs; see my home node.

In reply to Re^2: how apply large memory with perl? by aaron_baugher
in thread how apply large memory with perl? by xiaoyafeng

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