in reply to e
sub e{ use integer; my @e=(1) x shift; for(1..@e*log(@e)/3){ for(reverse(1..$#e)){ $e[$_-1]+=$e[$_]/$_; $e[$_]%=$_; } printf"%01d",$e[0]; $e[0]=0; $_*=10 for @e; } }
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Re^2: e
by tachyon (Chancellor) on Jul 17, 2004 at 07:28 UTC | |
by locked_user mtve (Deacon) on Jul 17, 2004 at 09:36 UTC | |